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finding the products of square roots
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\(\bf 7\sqrt{10}\cdot 3\sqrt{5}\implies 7\cdot 3\sqrt{10\cdot 5}\)
21 sqrt 50
yes, so |dw:1389230680459:dw| \(\bf 7\sqrt{10}\cdot 3\sqrt{5}\implies 7\cdot 3\sqrt{10\cdot 5}\implies 21\sqrt{50}\\ \quad \\ \color{blue}{ 50\implies 2\cdot 5\cdot 2\implies 2\cdot 5^2}\\ \quad \\ 21\sqrt{50}\implies 21\sqrt{2\cdot 5^2}\)
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