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how to find the product of (2n+3)(n-2)
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Don't think so. You need to FOIL.
(2n+3)(n-2)=2n2+n-6 is the product
2n^2+n-6
@DSS thank you so much
Sorry Maikel1234, that is incorrect. N can be any real number for this set, you can't "prove" anything and you certainly don't "prove" things by saying n is equal to a random number. Follow what DSS said about First Outside Inside Last.
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