Question

Write the equation of the line in standard form:
(-3, 6); m = 1/2
(1, 0) & (-5, 3)
(-5, -5) & (-1, 3)

Answer 1

Standard Form is Ax + By = C

(1)
\[y - 6 = \frac{1}{2} (x+3)\]
-->\[x - 2y = -15\]

(2)
\[y - 0 = m(x-1)\] and\[y - 3 = m(x+5)\]
So \[m = \frac{y-3}{x+5}\]
Substitute m into the first equation:
\[y = \frac{(y-3)(x-1)}{x+5}\]
Here you can do simplify by yourself. The result should be:
\[x + 2y = 1\]

(3) Do as similarly as the 2nd one