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Mathematics 9 Online
OpenStudy (anonymous):

cot(x+pi/2)=-tan x

OpenStudy (solomonzelman):

\[\huge\color{blue}{Cot~~(x+ \frac{π}{2} ) =-Tan~x}\] this?

OpenStudy (solomonzelman):

\[\huge\color{blue}{ Cot~(x +90)=-Tan~x }\] becuase π =180

OpenStudy (solomonzelman):

\[Cot~(x+90)~~~~~->~~~~\frac{Cos(x+90) }{Sin(x+90)} \] \[\sin(A+B)=\sin A \cos B + \cos A \sin B \]\[\cos(A+B)=\cos A \cos B - \sin A \sin B\] \[\frac{Cos(x+90) }{Sin(x+90)}=\frac{\cos(x)\cos(90)-\sin(x)\sin(90) }{\sin(x)\cos(90)+\cos(x)\sin(90) }\]

OpenStudy (solomonzelman):

\[\cos(90)=0~~~~and~~~\sin(90)=1.~~~~~~~~~So,\]the left side now becomes \[\frac{-Sin(x) }{Cos(x)} ~~~~~or,~~~~~~~-\frac{Sin(x) }{Cos(x)}~~~~~->~~~~~-Tanx\]

OpenStudy (solomonzelman):

So you now have \[-Tan(x)=-Tan(x)\] if you needed to verify the identity, verified. if you needed to solve for x, then infinite number of solutions.

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