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9x^3-43x^2-10x solve and show work please. Im stuck and need help please
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hold on let me try to figure this out.. I think I know how... give me a minute
okay
youre working on solving polynomials right?
yes
Are you solving\[9x^3-43x^2-10x=0\]? Do you see anything you can factor out there?
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umm yea the 9 and x
well, \(x\) anyhow. \[x(9x^2-43x-10)=0\]That means that \(x=0\) is one solution, right?
That leaves us with \[9x^2-43x-10=0\]You can factor that, or use the quadratic formula. Either way you should get two more solutions.
i would rather factor that, right
what do you get when you factor it? you must be a much better factoring fiend than I am :-)
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