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Cubed Roots HELP! I need to simplify 7x^3 - 56 7x^3 - 56 7(x^3 - 56) Now what? I know the answer, it is 7(x-2)(x + 2x + 4) but can someone please explain to me how they got there?
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I apologize it is 7(x^3 - 8)
You need to factor \(7(x^3 - 8)\) ?
The factorization of \(a^3 - b^3\) is as follows: \(a^3 - b^3 = (a - b)(a^2 + ab + b^2) \) This is known as a difference of cubes.
THANK YOU SO MUCH! That was the formula I couldnt remember!
You're welcome.
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