Question

integrand is |2x-3| ,upper limit is 2,lower limit is -1.Now I was asked evaluate the integral applying
perfect formula from geometry after sketching.
Please help ,my exam is Saturday,this question is related to my course.

Answer 1

\[\int\limits^2_{-1}|2x-3|\,\mathrm dx\]

Answer 2

the integrand is the absolute value of a straight line,

if you draw the graph of the integrand y=|2x-3|
you will see that the area under the 'curve' can be broken into triangular sections

Answer 3

what is the the y intercept of y=|2x-3|?
(what is y when x=0)

Answer 4

are you there @raselazam ?

Answer 5

yes

Answer 6

can you plot y=|2x-3|?

Answer 7

I have forgot the process

Answer 8

i like to start with finding the y-intercept ,

Answer 9

y=|2x-3|
when x=0,
y=?

Answer 10

3

Answer 11

yep , so