Question

f(x) is a differentiable function on the closed interval [-3, 7], with f(-3) = 4 and f(7) = 2.
There exists a value c, -3 < c < 7, such that:

f(c)=0
f'(c)=0
f'(c)=1/5
f'(c)= - 1/5
f'(c)= 5

Answer 1

Question?

Answer 2

@Abhishek619 yeah which one of those fits what they are saying

Answer 3

Oh, okay. I still feel there is something missing in the question.

Answer 4

f(c) =0

Answer 5

thanks! :)

Answer 6

np