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OpenStudy (anonymous):
Prove the identity 1-(cosx-sinx)^2=sin2x
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OpenStudy (loser66):
your attempt?
OpenStudy (loser66):
don't you have any idea?? Hint: open the bracket,
OpenStudy (anonymous):
(cosx-sinx)(cosx-sinx) ...? I'm not familiar with math that doesn't involve numbers. It took me so long to reply because I was on a cell phone and it was nearly impossible to type a reply.
OpenStudy (loser66):
yes, continue, please
OpenStudy (anonymous):
I'm honestly not sure how to continue. I guess 1-(cosx)^2-(sinx)^2=sin2x. Do I divide two?
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