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Mathematics 11 Online
OpenStudy (anonymous):

what is the square root of 36x to the 4th power sqrt[36x^(4)]

OpenStudy (the_fizicx99):

6x^2

OpenStudy (the_fizicx99):

Or, 6sqrt[x^4]

OpenStudy (anonymous):

but is the x^2 in absolute value brckets?

OpenStudy (the_fizicx99):

Nope

OpenStudy (anonymous):

thank yu ^*^

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