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Mathematics 7 Online
OpenStudy (anonymous):

Refer to the circle. Find the length of tangent side YZ http://media.education2020.com/evresources/647-11-05-00-00_files/i0220001.jpg

OpenStudy (jdoe0001):

|dw:1389310519440:dw|

OpenStudy (anonymous):

oh so 15^2+4^2=c^2? :)

OpenStudy (jdoe0001):

well... c = 15... so.... |dw:1389310826385:dw|

OpenStudy (jdoe0001):

\(\bf c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b\)

OpenStudy (anonymous):

oh so 15^2+4^2+b^2? thanks :) im gonna try to work it out now

OpenStudy (anonymous):

do i do square root over 15^2-2^2 together on my caculator or make them seperate like 15^2=225 and 4^2=16?

OpenStudy (jdoe0001):

depends on the calculator really if it's just a buttons one... then .... no graphic.... then ...hmm you'd get the 15[square button] - 4[square button] then the root button

OpenStudy (anonymous):

oh okay yeah your right. ill just square them seperate. i got 225 and 16

OpenStudy (jdoe0001):

https://www.desmos.com/ <-- maybe =)

OpenStudy (anonymous):

thanks for the link :)

OpenStudy (anonymous):

I got 14.45? o.o

OpenStudy (jdoe0001):

ooops... is 15... one sec dohh, I used 5 =)

OpenStudy (anonymous):

hahaha its okay. so thats the answer??

OpenStudy (jdoe0001):

yeap

OpenStudy (anonymous):

a. 19 c. 647-11-05-00-00_files/i0220002.jpg b. 60 d. 11

OpenStudy (anonymous):

sorry i messed up on c. its square root of 209

OpenStudy (anonymous):

but i think i know what we did wrongg here. i think its square root of 209.. lol

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