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Pre-Algebra
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The perimeter of a rectangular painting is 328 centimeters. If the width of the painting is 68 centimeters, what is its length?
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Do you know the formula for perimeter?
No :/ need helpp
ok, it's P= 2L+2W
The formula is: 2L + 2W = P (length times 2) + (width x 2) = Permineter So plug in your values. you know P is 328 and w is 68
2L + 2(68) = 328 and solve for L
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The rest is basic algebra.
From 2L +2(68) =328, 2L = 328-136 2L = 192 L = 96 right??
2*68=136. 328-136=192. 192/2=96. So yes, the length of the painting is 96 centimeters.
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