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Mathematics 10 Online
OpenStudy (rea201):

can someone help solve this. Find F'(x) for F(x)= Int((1/t^2)dt) Upper value=x^2 Lower value=2

OpenStudy (anonymous):

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OpenStudy (rea201):

ok so the answer is -1/x^2+1/2

OpenStudy (anonymous):

yep

OpenStudy (rea201):

Wow why didn't i know that . Duhh :) Thank you very much!!

OpenStudy (anonymous):

you are welcome

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