Question

Please help me!
Identify the focus,vertex,directrix,axis of symmetry, and latus rectum:
y=1/4 x^2
My answer is:
Please can you check my answers
vertex=(0,0)
focus=(0,1)
directrix=-1
axis of symmetry=0
how to find latus rectum

Answer 1

the latus rectum is the equation of the segment through the focus perpendicular to the y axis and has a length of |4a|

or the absolute value of 4 times the focal length

Answer 2

axis of symmetry is -b/2a. Axis of symmetry is also the x value so plug that number in to find the vertex.

Answer 3

the axis of symmetry is simply the x value in the vertex... in this question

x = .....

Answer 4

x would = 0 in this problem. Ax^2 +Bx +C there is no B or C so they both = 0

Answer 5

Please check my answers
vertex=(0,0)
focus=(0,1)
directrix=-1
axis of symmetry=0

Answer 6

r they right?

Answer 7

nope the axis of symmetry is an equation, in this case x = 0

Answer 8

Please show me how to get Latus rectum

Answer 9

the latus rectum is 4 times the focal length

and the focal length is the distance from the vertex to the focus