Solve the system.

x – 2y = 10
3x + 2y = 14

(–8, 6)
(–2, 6)
(6, –8)
(6, –2)

Question

Solve the system.

x – 2y = 10
3x + 2y = 14


       (–8, 6)
       (–2, 6)
       (6, –8)
       (6, –2)

anonymous · Answer

First, add the two fractions together, since the y values are opposite, they will cancel. You can therefore solve for x first.
  ( X-y=10)
+(3x+2y=14)
= (4x = 24)
= x = 6.
since x = 6,
6 -2y=10
-2y = 4
Y = -2

 (6,-2)

anonymous · Answer

can you help me with this too? @MRamosville 
  Select the pair of equations whose graphs are perpendicular.

       5x – 8y = 9
            12x – 5y = 7

       x + 6y = 8
            y = 2x – 8 

       y = 2x – 7
            x + 2y = 3

       2y = –3x + 5
            2x + 3y = 4