Question

olve: |5x + 2| + 7 < 19
A. x < 2 and x > -14/5
B. x < 2 and x < -14/5
C. x > 2 and x > 14/5
D. x > 2
Solve: |2x - 7| < 13
A. x < 10
B. x > 10 and x < -3
C. -3 < x < 10
D. x > -3
Solve: |2x - 7| < 13
A. x < 10
B. x > 10 and x < -3
C. -3 < x < 10
D. x > -3

Answer 1

please help.if not on all at least one

Answer 2

|5x + 2| + 7 < 19
Isolate the absolute expression.
subtract 7 from both sides:
|5x + 2| < 12
Whenever |A| < B it implies -B < A < B
Therefore, -12 < 5x + 2 < 12
subtract 2 from all three parts:
-14 < 5x < 10
divide by 5:
-14/5 < x < 2

Answer 3

|2x - 7| < 13 implies -13 < 2x - 7 < 13
solve for x the same way I did the first question.

Answer 4

thanks