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In the figure above, triangle ABC is similar to triangle ADE. If side AC = 4 cm, side CE = 2 cm and side BC = 3 cm, then what is the measure of side DE?
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see from the property of similiar triangles , u can tell that Ac/BC = AE/DE rite?
yea
ok and u can see that AE = AC+ CE :) now u can just substiture the value of AE in the above equation
and can find the value of DE, got it?
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Hope its clear, the answer shud be 4.5cm :)
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