Question

find the interval contain the solution to the following equation x^3 + 4.001x^2 + 4.002x + 1.101 =0

Answer 1

Let try
when x =-3, the expression = (-3)^3+4.001*(-3)^2+4.002*(-3)+1.001= -1.896
when x= -2 the expression = (-2)^3 +4.001*(-2)^2+4.002*(-2) +1.001= 1.001
therefore, there is one solution between -3 and -2

Answer 2

We will have 3 solutions, and all of them are negative. I think you can check one by one by this method