Solve:(-2x-5)+7x>-15
Someone plz help me
\[(-2x-5)+7x>-15\] \[-2x-5+7x>-15\] \[7x-2x-5>-15\] \[5x-5>-15\] \[5x>-15+5\] \[5x>-10\]... can you solve from here @Punkchick ?
no
sók, next step is to divide both sides by 5 so 5x/5 = ? and -10/5 = ? once you've done that, you'll have your final answer
would it be x<-2??
almost perfect, the symbol doesnt change direction though so x>-2
Can u help me on a couple more jack 1???
sweet, shoot
Solve: 2 (b-8)>12
you got this one already ;) in the other post
No I don't think so.
\[2 (b-8)>12\] expand out the brackets \[2b-16>12\] now add 16 to both sides \[2b>12+16\] now isolate the b by dividing both sides by 2 \[2b>28\] =...?
14
spot on, so b>14
Solve: 5x-6<9x+30
\[5x-6<9x+30\] ok i'll tell u the steps, and you do this one, k? \[5x-6<9x+30\] first, add 6 to both sides next, minus (9x) from both sides now you should have all the x numbers on one side, and all the plain numbers on the other side so finally, divide both sides by whatever number is left in front of the x ... = final answer now show me ur steps
???\
13,5
Am I I right???
mmm... could u show me the steps u went through, line by line, coz i got a diffrnt answer
I really need to know the answer
Could u plz tell me it
Am I right???
\[5x−6<9x+30\] first, add 6 to both sides \[5x−6+6<9x+30+6\] next, minus (9x) from both sides \[5x−6+6-9x<9x+30+6-9x\] now the -6+6 = 0 on the left hand side and the 9x - 9x= 0 on the right hand side so... \[5x-9x<+30+6\] now you should have all the x numbers on one side, and all the plain numbers on the other side 5x - 9x = ? and 30 + 6 = ? so finally, divide both sides by whatever number is left in front of the x ... = final answer
32
5x - 9x = -4x amd 30 + 6 = 36 so -4x<36 so times both sides by -1 means you flip the direction of the sign 4x>-36 x > -9
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