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Find sin 2theta and cos 2theta if tan theta= square root of two? I think I need to use a double-angle formula but I don't know which one or how to start, please help!
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u can express ..sin2theta and cos2theta in terms of tantheta also ..!
\[\sin2x=\frac{ 2tanx }{ 1+\tan^2x } ,,\cos2x=\frac{ 1-\tan^2x }{ 1+\tan^2x }\]
so sin2x=\[\frac{ 2\sqrt{2} }{ 3 }\]
and cos2x=-1/3
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