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OpenStudy (anonymous):
A stone is tied to string 0.5m long, and whirled at a constant speed of 4.0m/s in a vertical cirlce. What is its acceleration at the top of the circle ?
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OpenStudy (anonymous):
Centripetal acceleration is \[a = \frac{v^2}{r}\]
OpenStudy (anonymous):
Thank you @broken_symmetry ! Just wanted to make sure that it is not 9.8!
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