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Write 3exp(ix) - 3exp(-ix) in the Euler form? Is it 2i/3.sinx?
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Hint: \[3e^{ix}-3e^{-ix} = 6\frac{e^{ix}-e^{-ix}}{2}\]
No sorry, I am failing to see the hint :/
How did you get to your answer? You're on the right track.
Ah I've got it now! I was doing something rather stupid earlier on, but now I can see it. Thank you very much for your hint! :)
6i.sinx that is.
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Looks right to me =)
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