Question

help

Answer 1

21

Answer 2

\(\bf f(x)={\color{blue}{ x^2-3}}\qquad g(x)={\color{red}{ 2x+1}}\qquad (f\ o\ g)(x)=f(\quad g(x)\quad )\\ \quad \\
f(\quad g(x)\quad )={\color{blue}{ ({\color{red}{ 2x+1}})^2-3}}\)