Question

f(x)=(2x+3)(x-2)
find the vertex

Answer 1

I got (1/4,-95/16) but that's not right .

Answer 2

multiple choice?

Answer 3

I have to graph it

Answer 4

turn it to standard form
y=a(x-)^2+c so x=b is x of vertex
put it ant find y of vertex

Answer 5

\[f(x)=(2x+3)(x-2) = 2(x+\frac{ 3 }{ 2})(x-2)=2(x^2-\frac{ 1 }{ 2}x-3)\]
\[2(x^2-\frac{ 1 }{ 2}x-3)=2( (x-\frac{ 1}{4})^2-(\frac{ 1}{4})^2-3)=2(x-\frac{ 1}{4})^2-2((\frac{ 1}{4})^2-3)\]

Answer 6

so x of vertex is x=1/4