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Write the equation of the line that passes through (–4, 3) and is perpendicular to the line y=7/5x -3/5? A. 5x + 7y = 1 B. 7x + 5y = –13 C. 7x + 5y = –1 D. 3x + 5y = 7
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What is the slope of the line your equation is perpendicular to?
hint perpendicular line need to have a slope that is reciprocal with opposite sign than the original slope for ex if the original slope was 3 the the perpendicular slope would be -1/3
m (slope of the line given) m1 (slope of the line perpendicular) m.m1= -1 (you can find m1 from here) now equation of the required line becomes y=m1x+c to find c plug in the values of (x,y) ie the point through which it passes
@Zale101
find the reciprocal of the slope 7/5
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