Write the equation of the line that passes through (–4, 3) and is perpendicular to the line y=7/5x -3/5?

A.
5x + 7y = 1
B.
7x + 5y = –13
C.
7x + 5y = –1
D.
3x + 5y = 7

Question

Write the equation of the line that passes through (–4, 3) and is perpendicular to the line y=7/5x -3/5?

A.
5x + 7y = 1
B.
7x + 5y = –13
C.
7x + 5y = –1
D.
3x + 5y = 7

anonymous · Answer

What is the slope of the line your equation is perpendicular to?

anonymous · Answer

hint
perpendicular line need to have a slope that is reciprocal  with opposite sign than the original slope 
for ex if the original slope was 3 the the perpendicular slope would be -1/3

anonymous · Answer

m (slope of the line given) 
m1 (slope of the line perpendicular)
m.m1= -1  (you can find m1 from here) 
now equation of the required line becomes y=m1x+c 
to find c plug in the values of (x,y) ie the point through which it passes

sonyalee77 · Answer

@Zale101

zale101 · Answer

find the reciprocal of the slope 7/5

zale101 · Answer

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