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Mathematics 7 Online
OpenStudy (anonymous):

4n^-2 n=3 Would the set up be either 4(3^-2) or 4(3)^-2? And how do you do this :s

OpenStudy (smored):

first one \[4*\frac{ 1 }{ 3^{2} }\]

OpenStudy (smored):

4/9

OpenStudy (smored):

thanks for the yellow circle!

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