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find the constants m and b in the linear function f(x)=mx+b such that f(0)=2 and f(3)=-1
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f(0)=0m+b=2 b=2 f(3)=m(3)+2=-1 3m=-3 m=-1
Thank you! Been years since I have taken a math class. Wasn't sure how to set it up. I appreciate it.
Write out the unknown function: f(x)=mx+b. Now substitute x=0 (as smored has already done). Result: f(0)=0+b. We are told that f(0)=2. Therefore, as smored has demonstrated, f(0)=2=0+b, so b=2.
no prob!
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