Question

In rectangle ABCD, AC=4x+6 and BD=5x-1. Find the value of x.
A)9
B)3
C)7
D)6

Answer 1

5x-1=4x+6
solve

Answer 2

Simplifying
5x + -1 = 4x + 6

Reorder the terms:
-1 + 5x = 4x + 6

Reorder the terms:
-1 + 5x = 6 + 4x

Solving
-1 + 5x = 6 + 4x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x' to each side of the equation.
-1 + 5x + -4x = 6 + 4x + -4x

Combine like terms: 5x + -4x = 1x
-1 + 1x = 6 + 4x + -4x

Combine like terms: 4x + -4x = 0
-1 + 1x = 6 + 0
-1 + 1x = 6

Add '1' to each side of the equation.
-1 + 1 + 1x = 6 + 1

Combine like terms: -1 + 1 = 0
0 + 1x = 6 + 1
1x = 6 + 1
Combine like terms: 6 + 1 = 7
1x = 7

Divide each side by '1'.
x = 7

Simplifying
x = 7

Answer 3

We know that two diagonals in the rectangle are equal so,
in the given rectangle AC, BD are diagonals,,,,
AC = BD

Answer 4

i.e,
AC = BD
4x+6=5x-1

Answer 5

Not only diagonals opposite side are also equal in rectangle.....