Question

a piece of land in the shape of parallelogram whose altitude is one third its base if the perimeter is 200 m and its area is numerically equal to 8 times its perimeter find the length of diagonals

Answer 1

why base is 3x?

Answer 2

altitude is one third its base

Answer 3

base should be x and the altitude 1/3x?

Answer 4

altitude = x
then base = x/3,
area = x/3 * x
x^2 = 8*200*3
x^2=4800
x=40sqrt(3)

Answer 5

ok so I hav now the area, how can I found the diagonals?

Answer 6

d^2=sqrt(200^2+(40sqrt(3)^2)
d^2=sqrt(40000+4800)
d=80sqrt(7)