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Mathematics 20 Online
OpenStudy (anonymous):

What are the solutions of the equation: z2 - 12z + 36 = 0? A. -6, 6 B. 6, 6 C. 6, -6 D. -6, -6

OpenStudy (anonymous):

you have to solve for Z

OpenStudy (anonymous):

\[\left( z-6 \right)^{2}=0,z=6,6\]

OpenStudy (anonymous):

but i don't want to

OpenStudy (anonymous):

oh yeah z^2

OpenStudy (anonymous):

nice that if you mean z^2 you don't type it as z2 because it means something different. What makes you think we want to?

OpenStudy (anonymous):

lol @ehuman

OpenStudy (anonymous):

thanks @surjithayer

OpenStudy (anonymous):

np

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