Question

Solve, using the substitution method.

j + k = 3
j – k = 7

A.
The solution is (8, 1)

B.
The solution is (5, –2)

C.
There is no solution.

D.
There are an infinite number of solutions.

Answer 1

B is the correct option....

j+k=3............(1)
j-k=7 ............(2)

Add (1) n (2), you get:
2j=10
=> j = 5;

put back j in (1) or (2)
k=-2