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OpenStudy (anonymous):
standard form of (4+3i)²
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OpenStudy (anonymous):
(4+3i)² = (4)² + (3i)² + 2(4)(3i) = 16 + 9i² + 24i Since i² = -1, it becomes = 16 - 9 + 24i = 7+24i
OpenStudy (anonymous):
yes 7+24i
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