Question

Given the formula h = 1.5 sin [ 2π/ 12.4(t-4)] + 2.6, determine t when h=3.5.

I have this partially started, but I'm stuck where to go next.

h = 1.5 sin [ 2π/ 12.4(t-4)] + 2.6
3.5 = 1.5 sin [ 2π/ 12.4(t-4)] + 2.6
3.5 - 2.6 =1.5 sin [ 2π/ 12.4(t-4)]
.9 = 1.5 sin [ 2π/ 12.4(t-4)]
.9 / 1.5 = sin [ 2π/ 12.4(t-4)]
sin^-1 (.9 / 1.5) = 2π/ 12.4 (t-4)