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someone HELP ME!! plzzz
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hmm can you solve \(\bf x=-\cfrac{1}{8}y^2\) for \(y^2\) what would you get?
the sqrt of -1/8
hmm solving for \(y^2\) ?
\(\bf x=-\cfrac{1}{8}y^2\implies x=-\cfrac{1\cdot y^2}{8}\implies x=-\cfrac{y^2}{8}\)
ok i get tht
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so.... if you isolate \(\bf y^2\) what would be on the left-side?
-1/8x
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