Question

Precalc-
Find the angle between the given vectors to the nearest tenth of a degree.

u = <6, -1>, v = <7, -4>

20.3°

10.2°

0.2°

30.3°

Answer 1

let x be the angle between the vectors
then we have cos x = (6*7 +(-1)*(-4) )/ sqrt(37*65)
or x = cos-1 (46/sqrt(37*65))
or x = 43.17 appx

Answer 2

@matricked
are you sure thats right because these are the answer chioces
20.3°

10.2°

0.2°

30.3°

Answer 3

either my calculation is wrong or the check the question...