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Mathematics 7 Online
OpenStudy (ammarah):

find the inverse

OpenStudy (anonymous):

find the inverse of what?

OpenStudy (ammarah):

y=e^x+2

OpenStudy (anonymous):

thus we have e^x = y-2 taking log withe base e we have x = ln (y-2)

OpenStudy (ammarah):

i thought it was ln x-2=y

OpenStudy (anonymous):

Your thought is correct. The inverse is \(f^{-1}(x) = \ln(x-2)\)

OpenStudy (anonymous):

it is indeed ln(x-2)

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