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solve each equation
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\[-1+\left[ \frac{ a }{ 8 } \right]=0\]
a=8
-1 + ?=0
1 and -1 cancel each other out making it 0, so that means a/8 must equal one. a=8 because 8/8 is 1.
oohh
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@amoodarya
|dw:1389706108414:dw|
[x]=k ---> k<=x<k+1 when k is integer so [a/8]=1 1<=a/8 <1+1
where did you get k?
so \[1 \le \frac{ a }{ 8 } <1 \rightarrow 8 \le a<16\]
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k was a sample of integers like this look these equation \[\lfloor x \rfloor= 2 \rightarrow 2 \le x<2+1\] \[\lfloor 2x \rfloor=5 \rightarrow 5 \le 2x<5+1 \rightarrow \frac{ 5 }{ 2 }\le x<3\]
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