Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

Quadrilateral OPQR is inscribed in circle N as shown below. What is the measure of ∠OPQ?

OpenStudy (anonymous):

OpenStudy (anonymous):

Will give medal! help please!

OpenStudy (anonymous):

@RadEn can I please get help

OpenStudy (raden):

hint : O + Q = 180

OpenStudy (raden):

so, x+16+6x-4 = 180 solve for x, first

OpenStudy (raden):

got it ?

OpenStudy (anonymous):

not really so do i combine like terms

OpenStudy (raden):

yes, combine the like terms then solve for x. what do you get ?

OpenStudy (anonymous):

I got 26 but I think I did it wrong

OpenStudy (raden):

x+16+6x-4 = 180 7x + 12 = 180 7x = 180 - 12 7x = 168 x = 168/7 = 24

OpenStudy (anonymous):

So thats my final answer?

OpenStudy (raden):

no, that is a start :)

OpenStudy (anonymous):

oh ok can you help me with the other step please

OpenStudy (anonymous):

and thank for not juts giving me the answer.......I want to learn how to do it to

OpenStudy (raden):

look at the diagram once again. we knowed that O + Q = 180, and P + R = 180 too

OpenStudy (anonymous):

yeah I can se it

OpenStudy (raden):

known R = 2x + 16 we have x = 24, so distribute x = 24 into equation of R, first. R = 2x + 16 = 2(24) + 16 = 48 + 16 = 64

OpenStudy (raden):

recall that : P + R = 180 P + 64 = 180 P = 180 - 64 P = 116

OpenStudy (raden):

P is as the measure of OPQ. so, OPQ = 116 hope that make sense

OpenStudy (anonymous):

Thank you,can you help me with some questions from my test please.......I am very confused

OpenStudy (raden):

this site might useful : http://www.geom.uiuc.edu/~dwiggins/conj47.html

OpenStudy (anonymous):

No its like diffrent questions

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!