Question

NEED THIS DONE BY MIDNIGHT PLEASE HELP!?


Each child ticket for a ride costs $3, while each adult ticket costs $5. If the ride collected a total of $115, and 33 tickets were sold, how many of each type of ticket were sold?

Answer 1

Is it multiple choice?

Answer 2

YES

Answer 3

Plug in each choice until one matches up

Answer 4

That's how I do those problems when in doubt :P

Answer 5

ok thanks i'll try

Answer 6

what are your choices

Answer 7

8 child and 25 adult
17 child and 16 adult
156 child and 41 adult
25 child and 8 adult

Answer 8

3c+5a=115

Answer 9

\(\large \begin{array}{lcccllll}
&\textit{tickets sold}&\textit{price for each}&\textit{total for all}\\
\hline\\
children&c&3&3c\\
adults&a&5&5c\\
\hline\\
&c+a=33&&3c+5c=115
\end{array}\)

if you were to solve say c+a=33 for "a", what would you get?

Answer 10

hmmm I even have a typo... hmm ok well \(\large \begin{array}{llll}
&\textit{tickets sold}&\textit{price for each}&\textit{total for all}\\
\hline\\
children&c&3&3c\\
adults&a&5&5c\\
\hline\\
&c+a=33&&3c+5a=115
\end{array}\)

Answer 11

yet anotehr typo shoot \(\large \begin{array}{lccclll}
&\textit{tickets sold}&\textit{price for each}&\textit{total for all}\\
\hline\\
children&c&3&3c\\
adults&a&5&5a\\
\hline\\
&c+a=33&&3c+5a=115
\end{array}\)

anyhow, solve the 1st equation c+a=33 by "a" first

Answer 12

ohh ok i understand now!

Answer 13

thank you so much!

Answer 14

yw

Answer 15

do you have time for more?

Answer 16

easier to post anew... gives more exposure, thus more answers and we can also revise each other :)