Question

What is the axis of symmetry for the graph of y=2x^2-8x+2
x=?

Answer 1

is it 3

Answer 2

x = -2

Answer 3

how did you get that

Answer 4

Find algebraically the equation of the axis of symmetry and the coordinates of the vertex of the parabola whose equation is y=-2x^2-8x+3
..
y=-2x^2-8x+3
completing the square
y=-2(x^2+4x+4)+3+8


y=-2(x+2)^2+11
Standard form of parabola: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex. A is a multiplier which affects the steepness or narrowness of the parabola.
For given parabola, coordinates of the vertex at (-2,11), axis of symmetry, x=-2