Question

What is the radius of the circle shown below?
x^2+y^2-12x-6y-4=0

Answer 1

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Answer 2

this is the general equation for circle,
the general eqn is this:
x^2+y^2+2gx+2fy+c=0
the centre is: (-g, -f), in this case the centre is (-6, 3)
the radius is: (g^2+f^2-c)^1/2, in this case the radius is 7.

Answer 3

(x-h)^2=(y-k)^2=r^2
r=7
k=3
h=6

Answer 4

the center is 6,3