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------MEDAL AND FAN!!!--------- Write three other expressions that are equivalent to 8x-12.
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\[\sqrt{8x-12}^{2}\] 8x -8 -4 8(x-1,5)
Well since x is completely arbitrary, you can just substitute some other thing in for x that's equally arbitrary, and to reduce confusion, we'll call the other variable something like, t. x=t+1 plug it in: 8(t+1)-12 8t+8-12 8t-4 And if you want, you can just call t as x again if that makes you happy. 8x-4. So there's one.
Ok thanks! I need 2 more =(
Sounds like you need to use your noggin' and use the help provided to _understand_ it so that you can officially call what you're doing as: learning.
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