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How do u solve (2/p)^-3
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Does it ask for a simplified form?
Yea
okay then (2/p)^-3=(2^-3)/(p^-3) then u can simplify it further...
\(\bf a^{-{\color{red} n}} = \cfrac{1}{a^{\color{red} n}}\\ \quad \\ \quad \\ \left(\cfrac{2}{p}\right)^{-3}\implies \cfrac{2^{-3}}{p^{-3}}\implies \cfrac{\frac{1}{\square ?}}{\frac{1}{\square ?}}\\ \quad \\ \cfrac{1}{\square ?}\cdot \cfrac{\square ?}{1}\)
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