square root of negative 3 times the square root of negative 108
\(\Huge\bf Welcome~to~ \color{#00B4ff}{Open}\\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\Huge\bf\color{#7cc517}{Study~!!}~\) The answer would be -18
hmm what would the imaginary number be though..
\(\large Since~you~seem~new~here:\\\bf\Huge{~~\color{red}{\boxed{W}}\color{#FF9200}{\boxed{E}}\color{#FFDB00}{\boxed{L}}\color{#B6ff00}{\boxed{C}}\color{#00ff49}{\boxed{O}}\color{#00DBff}{\boxed{M}}\color{#B600ff}{\boxed{E}}\\~~~~~~~~~~~~~~~~~~\boxed{T}\boxed{O}\\~~~~~~~~~~~\color{#0092ff}{\boxed{O}}\color{#0092ff}{\boxed{P}}\color{#0092ff}{\boxed{E}}\color{#0092ff}{\boxed{N}}\color{#7cc517}{\boxed{S}}\color{#7cc517}{\boxed{T}}\color{#7cc517}{\boxed{U}}\color{#7cc517}{\boxed{D}}\color{#7cc517}{\boxed{Y}}\color{#7cc517}{\boxed{!}}} \\ \large\bf You~can~read~the~\underline{\href{ /code-of-conduct }{Code~of~Conduct}}~here. • \\ \it \large Now~let's~try~to~find~an~answer~to~your~problem~together.\)\ Hi, It would, in fact, be negative eighteen. To be precise i18
The imaginary number isn't applicable because this expression can be evaluated and solved without the use of imaginary numbers, nor does it produce one.
okay, sorry. I was trying to figure out how to put into an a+bi form its what it is asking me.
Evaluate the expression √ −3 √ −108 and write the result in the form a+bi.
He wants a complex number and a real one
I am so stupid. Nevermind.
Ha ha, did you have an epiphany?
Yeah, i was so stupid. I was like then how the heck do you write the complex number... obviously there wasnt one so it was -18 + 0i
err you know what i mean
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