Question

What is the center and radius for equation x^2+y^2+6x-16y+48=0

Answer 1

well complete the square in x and y

start by grouping things

\[(x^2 + 6x) + (y^2 -16y) = -48\]

Answer 2

\(\bf (x^2 + 6x+{\color{red}{ \square }}?) + (y^2 -16y+{\color{red}{ \square }}?) = -48\)

Answer 3

\(\bf (x^2 + 6x+{\color{red}{ \square }}^2) + (y^2 -16y+{\color{red}{ \square }}^2) = -48\)