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3y-12>5y+10
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to solve for the y variable, you want to get the y-variable on one side
Since 3y is smaller than 5y, you can subtract to avoid negatives and it would look like this: 3y-12>5y+10 -3y -3y ------------ -12>2y+10 or 2y+10<-12 (they're both the same things)
does this make sense so far? @jaywale ?
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