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Write an equation in slope-intercept form for the line that satisfies each set of conditions. Passes through (-9,-3), perpendicular to y=-5/3-8
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The perp of -5/3 is 3/5 Y-y1=M(x-x1) Y-(-3))=3/5(x-(-9))
Solve dat
y=3/5x+6 ?
ok so first tell me what you thimk you should...when you respond to me tag my name
so now what do I do ? is this right so far y=3/5x+6
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looks correct to me.
now do I have to solve for b by putting in this formula y=mx+b ?
Someone help please!!!!
y - (-3) = 3/5 * (x - (-9)) y + 3 = 3/5x + 27/5 y = 3/5x + 27/5 - 3 y = 3/5x + (27 - 15) / 5 y = 3/5x + 12/5 is the equation of the line in slope intercept form.
Sorry I was afk >.<
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Thanks ranga!
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