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Mathematics 18 Online
OpenStudy (anonymous):

Algebra 2 help

OpenStudy (anonymous):

@ash2326 help please?

OpenStudy (ash2326):

you have denominators as x+4 and 2x. Can you find the LCM of these two?

OpenStudy (anonymous):

2x(x+4)

OpenStudy (ash2326):

yes, can you simplify it?

OpenStudy (anonymous):

2x^2+8 or is it 2x+8

OpenStudy (ash2326):

\[2x (x+4)\] \[=2x \times x + 2x\times 4\] \[=2x^2+8x\]

OpenStudy (anonymous):

ok and from there what would i do

OpenStudy (ash2326):

you asked if denominator is 12x. It can't be 12x

OpenStudy (anonymous):

so thats the final denominator?

OpenStudy (ash2326):

yes sir

OpenStudy (anonymous):

lol ok thanks.

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