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solve each equation for variable. 2log X= log 25
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x=5
but how? :\
http://www.algebra.com/algebra/homework/logarithm/logarithm.faq.question.281036.html
thankss!!!
go there and you will find it i have to go so click on that link and it will explain everything
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no probs
\(\bf 2log(x)= log 25\qquad \textit{log rule of }a\ log(b)=log(b^a)\\ \quad \\ {\color{red}{ 2}}log(x)= log 25\implies log(x^{\color{red}{ 2}})= log(25)\implies log(x^{\color{red}{ 2}})= log(5^{\color{red}{ 2}})\)
thank youu!!
yw
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