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what is the domain of y=x*sq rt of (2-x^2) and why?
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First of all, whatever is inside the square root has to be greater of equal to 0, right?
So, 2-x^2>=0 x^2<=2 -sqrt(2)<=x<=sqrt(2)
i do not understand how you got that last line
i got x<= positive and negative sqrt of 2
Do you know how to graph y=x^2?
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and y=2?
yes
Can you draw both of the graphs on the same coordinate plane for me?
oops
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